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Afina-wow [57]
3 years ago
11

20 POINTS PLZ HELP

Mathematics
1 answer:
blondinia [14]3 years ago
3 0

Answer:

It would be a straight line.

Step-by-step explanation:

It would be a negative, linear line. It would be steep.

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Select the expression that has a value of 62.35.
ss7ja [257]

Answer:

D

Step-by-step explanation:

You cannot divide a decimal by a full number and also you move the decimal too places too the right so the bottom option

6 0
3 years ago
Read 2 more answers
Equations Review Homework
sattari [20]

Answer:

10x + 50 = 90; 4 hours

Step-by-step explanation:

Let

x -----> the number of hours

y ----> the total charge

we know that

The total charge is equal to the number of hours multiplied by the rate of $10 per hour plus a flat fee of $50

so

The linear equation that represent this problem is

y=10x+50

For y=$90

substitute in the equation and solve for x

90=10x+50

Subtract 50 both sides

90-50=10x+50-50

40=10x

Divide by 10 both sides

x=4\ hours

therefore

10x + 50 = 90; 4 hours

6 0
3 years ago
Write using exponents. (–4)(–4)<br><br> A. -4^2 <br> B. (2)^-4 <br> C. (-4)^2 <br> D. 2^-4
expeople1 [14]

Remark

Using brackets, as the question has, each of the minus signs is part of the 4. That means you have 2 minus signs in total. They are multiplied together.


Two minus sign's = a plus.


Argument

D is wrong.

The power is not made minus. That would be an entirely different problem. The power and the base have been interchanged. So D has 2 mistakes.


B is also wrong for the same reason.

The power and base have been interchanged. The fact that there are or are not brackets does not make any difference.


A is wrong.

There is only one minus sign given. That cannot happen when there were two to start with.


Answer C.

The two minus signs are preserved. The 2 as a power affects both minus signs.


(-4)^{2} affects both of them.

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3 years ago
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Https://www.symbolab.com/solver/algebra-calculator/x%2By%3Dz%3Bx
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Give me authentic answers please.
nataly862011 [7]
B - the value of x is positive and the value of y is negative
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