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Inessa [10]
3 years ago
6

Stuart bought a sweater that was on sale for 30% off the regular price. He also had an additional 25% off coupon. If the origina

l price was $30, how much did he pay for the sweater?
Mathematics
1 answer:
never [62]3 years ago
7 0

Answer:

Step-by-step explanation:

The original price of the sweater that Stuart bought was $30.

The sweater was on sale for 30% off the regular price. This means that the amount of money that was removed from the original price is

30/100 × 30 = 0.3 × 30 = 9

The price at which the sweater was offered for sale would be

30 - 9 = $21

He also had an additional 25% off coupon. The value of the coupon would be

25/100 × 21 = 0.25 × 21 = $5.25

Therefore, the amount that he paid for the sweater would be

21 - 5.25 = $15.75

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Answer:

  CPCTC

Step-by-step explanation:

Statements 3 and 4 show the top and bottom triangles are congruent, and the left and right triangles are congruent. Statement 5 is making use of these facts to claim that the alternate interior angles are congruent. This claim is valid because ...

  Corresponding Parts of Congruent Triangles are Congruent (CPCTC)

7 0
3 years ago
Which set is an example of like fractions 1/2 and 3/2, 10/10 and5/5 ,7/4 and 4/7, 2/1 and 2/3
NeTakaya
10/10 and 5/5 are like fractions
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3 years ago
6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0
3 years ago
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Answer:

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Step 1: Simplify both sides of the equation.

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Step 2: Add 40 to both sides.

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Step 3: Divide both sides by 8.

8x/8=76/8

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Answer:

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