Answer: time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Explanation:
For an RC Charging circuit
Where Vs
Vc = Vs (1 - e^(-t/RC))
Vc/Vs = 1 - e^(-t/RC)
-t/RC = ln(1 - Vc/Vs)
t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)
Where ;
Vc = voltage across the capacitor
Vs = voltage supply
t = charging time = 2.5ms
k = RC = time constant.
Vc/Vs = 0.35
To calculate the time constant k;
k = -t/ln(1- Vc/Vs)
k = -2.5/ln(1-0.35)
k = 5.80ms
time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Answer : Height, h = 20.4 m
Explanation :
It is given that,
Mass of an object, m = 500 g = 0.5 kg
Gravitational potential energy, PE = 100 J
The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :
PE = m g h
where,
h is the height of the cliff.

h = 20.40 m
So, the height of the cliff is 20.4 m.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
Give the relation of resistance of wire with the length and thickness:
Resistance:
There is a resistance to the flow of an electric current through most conductors.
The length of wire increases
The thickness of wire decreases
The resistance of a long wire is greater then the resistance of a short wire because electrons collide with more ions as they pass through.
The relationship between resistance and wire length is proportional. The resistance of thin wire is greater then the resistance of a thick wire because a thin wire has fewer electrons to carry the current.The relationship between resistance and the area of the cross section of wire is inversely proportional.
Answer:
Distance = πr
Displacement = 2r
Explanation:
First we need to find the distance covered by the car. As the car is travelling on a circular path and it traveled to a diametrically opposite point on the circular path. Therefore, the distance covered by the car must be the half value of the circumference.
Distance = Circumference/2
Distance = 2πr/2
<u>Distance = πr</u>
Since, displacement is the straight line distance between two points. So, the displacement in moving from a point to its diametrically opposite point must be equal to the diameter of circle:
Displacement = Diameter
<u>Displacement = 2r</u>