A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren
1 answer:
Answer : Height, h = 20.4 m
Explanation :
It is given that,
Mass of an object, m = 500 g = 0.5 kg
Gravitational potential energy, PE = 100 J
The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :
PE = m g h
where,
h is the height of the cliff.
h = 20.40 m
So, the height of the cliff is 20.4 m.
You might be interested in
Question:
A particle moving along the x-axis has a position given by x=(24t - 2.0t³)m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero
Answer:
24 m/s
Explanation:
Given:
x=(24t - 2.0t³)m
First find velocity function v(t):
v(t) = ẋ(t) = 24 - 2*3t²
v(t) = ẋ(t) = 24 - 6t²
Find the acceleration function a(t):
a(t) = Ẍ(t) = V(t) = -6*2t
a(t) = Ẍ(t) = V(t) = -12t
At acceleration = 0, take time as T in velocity function.
0 =v(T) = 24 - 6T²
Solve for T
Substitute -2 for t in acceleration function:
a(t) = a(T) = a(-2) = -12(-2) = 24 m/s
Acceleration = 24m/s
Answer:
Explanation:
Kinetic Energy formula:
KE = mv²
m=mass
v=speed
Given:
m=0.25kg
v=2.5m/s
Plug the values in:
KE = 1/2(0.25kg)(2.5m/s)²
KE = 0.78125 J (Joules)
Answer:
Energy = 7.83 x 10⁻¹⁹ J
Energy = 6.63 x 10⁻¹⁹ J
Explanation:
The energy of a photon in terms of wavelength can be calculated by the following formula:
where,
h = Plank's Constant = 6.63 x 10⁻³⁴ Js
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
Now, for λ = 254 nm = 2.54 x 10⁻⁷ m:
<u>Energy = 7.83 x 10⁻¹⁹ J</u>
<u></u>
Now, for λ = 300 nm = 3 x 10⁻⁷ m:
<u>Energy = 6.63 x 10⁻¹⁹ J</u>