Active Optics.
Hope that helps, Good luck! (:
Answer:
xf = 5.68 × 10³ m
yf = 8.57 × 10³ m
Explanation:
given data
vi = 290 m/s
θ = 57.0°
t = 36.0 s
solution
firsa we get here origin (0,0) to where the shell is launched
xi = 0 yi = 0
xf = ? yf = ?
vxi = vicosθ vyi = visinθ
ax = 0 ay = −9.8 m/s
now we solve x motion: that is
xf = xi + vxi × t + 0.5 × ax × t² ............1
simplfy it we get
xf = 0 + vicosθ × t + 0
put here value and we get
xf = 0 + (290 m/s) cos(57) (36.0 s)
xf = 5.68 × 10³ m
and
now we solve for y motion: that is
yf = yi + vyi × t + 0.5 × ay × t
² ............2
put here value and we get
yf = 0 + (290 m/s) × sin(57) × (36.0 s) + 0.5 × (−9.8 m/s2) × (36.0 s) ²
yf = 8.57 × 10³ m
Force = (mass) · (acceleration)
= (1,000 kg) · (9.8 m/s²)
= 9,800 newtons
Why are you still having a problem with F = M · a ?
Answer:
Explanation:
Distance travelled = 600 - 500 = 100 m
Time taken = 9:03:25 a.m.- 9:03 :05 a.m.
= 20 s
average speed = distance / time taken
= 100 / 20 m /s
= 5 m /s