Answer:11 and 12 is g and g and answer 13 is 5.36487494991
Step-by-step explanation:
Answer:
seven hundred ninety-five billion eight hundred million nine hundred thirteen thousand seven hundred eighty-nine
The question is incomplete. Here is the complete question.
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.
a) Determine the arc length to the nearest tenth of an inch.
b) Explain why the following proportion would solve for the length of AC below: 
c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.
Note: The image in the attachment shows the arc to solve this question.
Answer: a) 9.4 in
c) x = 13.6 in
Step-by-step explanation:
a)
, where:
r is the radius of the circumference
mAB is the angle of the arc
arc length = 
arc length = 
arc length = 9.4
The arc lenght for the image is 9.4 inches.
b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):


c) Resolving (b):
x = 
x = 13.6
The arc length for the image is 13.6 inches.
You have to find the difference in height between both checkpoints. To do this just calculate 196 - 52. Checkpoint 5 is 144 (meters?) higher than Checkpoint 2.
consider first number is = x
formula,
(n / 2)(first number + last number) = sum,
7/2(x+x+6)= 945
2x+6= 945×2/7
2x+6 = 270
2x= 270-6
x=264/2= 132
Answer the smallest number is 132.