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3 years ago

How do I solve h(x)=2x + 7 and solve with 8

Mathematics

1 answer:

Radda [10]3 years ago

4 0

Answer:

h(x)=2x+7

h(8)=2(8)+7

h(8)=16+7

h(8)=23

Step-by-step explanation:

Put 8 in h(x) and simplify the equation.

In other words, put 8 wherever you see x and simplify the equation.

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What is the cost of the following?

Savatey [412]

$1.\\
6\ cans\\
3\ cans\ cost\ 1\$\\
1\ can\ cost\ \frac{1}{3}\$\\
6*\frac{1}{3}\$=\frac{6}{3}\$=2\$\\\\ \textbf{6\ cans\ cost\ 2\$}\\\\2.\\ 3\ boxes\ of\ cereal\\1\ box\ costs\ 0,99\$\\
3*0,99\$=2,97\$\\\\
\textbf{3\ boxes\ of\ cereal\ cost\ 2,97\$.}\\\\
3.\\
1\ loaf\ of\ bread\ cost\ 0,45\$\\
1*0,45=0,45\$\\\\
\textbf{One\ loaf\ of\ bread\ costs\ 0,45\$}\\\\
4.\\
6\ lbs\\
2\ lbs\ cost\ 0,8\$\\
1\ lbs\ costs\ 0,4\$\\
6*0,4\$=2,4\$\\\\
\textbf{6\ lbs\ of\ aplles\ cost\ 2,4\$}$ $5.\\
1\ box\ of\ jello\\
2\ boxes\ of\ jello\ cost\ 0,54\$\\
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\textbf{1\ box\ of\ jello\ costs\ 0,27\$.}$

5 0

4 years ago

Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

3 years ago

you are assigned 25 spelling words to master you memorize 60% of the words how many do you have left to memorize

Volgvan

2.5 is 10% of 25. 2.5 * 6 = 15 = 60%

25 - 15 = 10. You have 10 words left to memorize.

I hope this helps.

5 0

4 years ago

Keith works 8 hours per day for 5 per week. melba works 2,250 minutes each week. who spends more time at work

Orlov [11]

Answer:

Keith does.

Step-by-step explanation:

2250/60=37.5

8*5=40

Keith spends 40 hrs at work Melba spends 37.5 hrs.

6 0

4 years ago

What is the difference between -4=7 vs 5=5

KiRa [710]

Answer:

{-4 = 7, 5 = 5} = {False, True}

Step-by-step explanation:

3 0

3 years ago