Answer:
Adults=8
Childrens=2
Seniors=2
Step-by-step explanation:
Children $4
Adults $6
Seniors $5
There are an equal number of seniors and children.
The entire group spent a total of $66.
If 11 adults attended, the total amount will be $66 and the number of senior and childrens will be the same, 0. But this is not possible because the statement says that childrens and seniors are part of the group.
If we add the charges of childrens and seniors is equal to $9.
Assuming that the group has 2 childrens and 2 seniors the add is equal to:
Now we substract the result from the total amount:
48 is multiple of 6, this means we have in the group 8 adults, 2 childrens and 2 seniors.
Answer:
I think the answer should be Mat A cause it has more space.
Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Step-by-step explanation:
Given that;
p = 10% = 0.1
so let q = 1 - p = 1 - 0.1 = 0.9
n = 818
μ = np = 818 × 0.1 = 81.8
α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58
Now to find P( x < 100)
we say;
Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12
P(x<100) = P(z < 2.12)
from z-score table
P(z < 2.12) = 0.9830
Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Answer:
Jamie is correct
Step-by-step explanation:
Jamie is correct.
Example: isosceles triangle ABC AB=AC
∠B = ∠C ∠A + ∠B + ∠C = 180°
if ∠A = x ∠B = ∠C = 1/2 * ( 180° - x)
if ∠B or ∠C = x ∠A = 180° - 2x
Can you show the whole question
