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3 years ago

Find the length of a side of a square if its área is 4/25 cm2

Mathematics

1 answer:

USPshnik [31]3 years ago

4 0

Answer:

2/5cm or 0.4cm

Step-by-step explanation:

Area of square = $Side^{2}$

Thus, Side = $\sqrt{Area}$

= $\sqrt{4/25}$

= 2/5 cm = 0.4cm

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2. What is the equation in slope-intercept form of the line that passes through thepoints (-4, 47) and (2, -16)?O21 979y=-2*+ 21

trapecia [35]

hello

the points given are (-4, 47) and (2, -16)

let's find the intercept of this equation

$\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ x_2=2 \\ y_2=-16 \\ y_1=47 \\ x_1=-4 \end{gathered}$ $\begin{gathered} m=\frac{-16-47}{2-(-4)} \\ m=-\frac{21}{2} \\ slope=-\frac{21}{2} \end{gathered}$

now, since we know the value of the slope, we can use that in the standard equation on a straight line

the standard equation of a straight line is given as

$\begin{gathered} y=mx+c \\ m=\text{slope} \\ c=\text{intercept} \end{gathered}$

we can pick any of the points and solve for intercept

let's use (2, -16)

$\begin{gathered} x=2 \\ y=-16 \\ y=mx+c \\ m=-\frac{21}{2} \\ -16=-\frac{21}{2}(2)+c \\ -16=-21+c \\ \text{collect like terms} \\ c=-16+21 \\ c=5 \end{gathered}$

now we know the value of intercept (c) = 5 and the slope (m) = 21/2

let's use this to write equation of the straight line

$\begin{gathered} y=mx+c \\ y=-\frac{21}{2}x+5 \end{gathered}$

from the calculations above, the equation of the straight line is given as y = -21/2x + 5

8 0

1 year ago

PLS HELP!<br><br> 45-[38-{60÷3-(6-9÷3)÷3}]

Rom4ik [11]

It’s 18 typing typing typing

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3 years ago

Read 2 more answers

Can some one can do both

patriot [66]

A) m=-3
B) n=-17
hope this helps x
would love to have brainliest if it is right :)

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A manager bought lunch for his coworkers. Each person picked either a salad or a burger. The salads cost $5 each and the burgers

Monica [59]

Answer: 8

Step-by-step explanation: You divide 102/13=7.84615385. Rounded answer 8.

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2 years ago

A2+b2 = C2solve for a

lesantik [10]

$a^2+b*2=c^2$

$a^2+2b=c^2

$ $\text{Regroup terms}$

$a^2=c^2-2b
$ $\text{Subtract 2b from both sides}$

$a=\pm \sqrt{c^2-2b}$ $\text{Take the square root of both sides}$

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3 years ago