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2 years ago

6

Please help also worth 10 points

2 answers:

tino4ka555 [31]2 years ago

4 0

Answer:

A.

D= <u>1</u> wy

5

<u>D</u> = <u>1</u> wy (cross multiplication)

1 5

wy= 5D ( cancel y to get w)

<u>wy</u> = <u>5</u>D

y = y

w=<u>5</u><u>D</u>

y

Scorpion4ik [409]2 years ago

3 0

The answer is A- 5D/y

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Factor out the GCF from the terms of the polynomial –4y5 + 6y3 + 8y2 – 2y. A. –2y4 + 3y2 + 4y – 1 B. y(–4y4 + 6y2 + 8y – 2) C. 2

andreyandreev [35.5K]

Answer:

Option D) $-2y(2y^4-3y^2-4y+1)$ is correct

Therefore $-4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)$

Step-by-step explanation:

Given polynomial is $-4y^5+6y^3+8y^2-2y$

To factorise the given polynomial by taking out the common terms of the given polynomial :

$-4y^5+6y^3+8y^2-2y$
$=2y(-2y^4+3y^2+4y-1)$ ( here 2y is GCF common term so taking outside the terms of the polynomial )
$=-2y(2y^4-3y^2-4y+1)$ ( now taking (-) outside )

Therefore $-4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)$

Option D) $-2y(2y^4-3y^2-4y+1)$ is correct

8 0

3 years ago

A survey of teens suggested that 33% can name at least one professional baseball player, and 90% of those teens can also name at

loris [4]

Answer:

$d.\ 0.33 + 0.64 – (0.90)(0.33) = 0.673$

Step-by-step explanation:

Given

$P(Baseball) = 33\%$

$P(Baseball\ n\ Football) = 90\%$

$P(Football) = 64\%$

Required

$P(Baseball\ or\ Football)$

This is calculated as:

$P(Baseball\ or\ Football) =P(Baseball) + P(Football) -P(Baseball\ n\ Football)$

$P(Baseball\ or\ Football) = 0.33 + 0.64 - (0.90)(0.33)$

$P(Baseball\ or\ Football) = 0.33 + 0.64 - 0.297$

$P(Baseball\ or\ Football) = 0.673$

3 0

2 years ago

Please help<br> Honestly cant understand

cluponka [151]

Answer: x=20°

Explanation: Since UTX is a diameter, it is equal to 180°. You can now set up the equation (4x+2)+x+78=180. Then solve for x.

You should get, x=20.

4 0

2 years ago

In the diagram of RST, what are the two smaller angles?

ruslelena [56]

Answer:

34

Step-by-step explanation:

6 0

2 years ago

A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller,

zhuklara [117]

Answer:

$285.74\text{ inch}^2$

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of $3\text{ inch}$ . The bicycle wheel has a radius of $10\text{ inch}$ .

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel $=10\text{ inch}$

area of bicycle wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times10^2$

$=314\text{ inch}^2$

radius of bicycle training wheel $=3\text{ inch}$

area of bicycle training wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times3^2$

$=28.26\text{ inch}^2$

difference in area of bicycle wheel and bicycle training wheel

$=\text{area of bicycle wheel}-\text{area of bicycle training wheel}$

$=314-28.26$

$=285.74\text{ inch}^2$

hence the training wheel is $285.74\text{ inch}^2$ smaller than regular wheel

4 0

2 years ago