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adell [148]
3 years ago
12

Janelle requested one statistics book from two different libraries of her neighborhood. There is 52% chance that the book is ava

ilable in the first library and there is 25% chance of its availability in the second library.
The probability that Janelle can check out the statistics book from the second library and not from the first library is _____.
a .12
b .36
c .25
d .75
e .52


The probability that the book is not available for checkout at either of the libraries is ____.
a .52
b .75
c .25
d .12
e .36
Mathematics
1 answer:
Advocard [28]3 years ago
7 0
For the first one is definitely 0.12 
The second one I was having trouble with, but I know it is not .25 or .75. Looking at the leftover answers I would say .36 because I already used .12. Also .52 and .25 are the givens.
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Answer:

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Step-by-step explanation:

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3 years ago
Find the mean of 81, 97, 99, 89, 91, 76 (round to the hundredths)
Marta_Voda [28]

Answer:

88.83

Step-by-step explanation:

To find the mean of a set of numbers is to find the average a set of numbers.

To solve for the mean you have to add all of the values together and divide that sum by the number of values there are.

Ex. 81, 97, 99, 89, 91, 76

     81 + 97 + 99 + 89 + 91 + 76 = 533

     533 / 6 = 88.83

               ↓

     (number of values)

3 0
3 years ago
Question: Which number is divisible by 5 and 10?
Harrizon [31]

Answer:

9,450

Step-by-step explanation:

10 cant go into the others because they end with a 5

8 0
2 years ago
Simon says that to find the area of a trapezoid, you can multiply the height by the top base and the height by the bottom base.
Vlad [161]
The last one is 1/2. what is the choices of the questions
7 0
2 years ago
3
iren2701 [21]

Answer:

B

D

A

Step-by-step explanation:

Given:

A. 2x^3-x^{2} -6x

B. 2x^3+8x+4

C. 3x^4+x^{2} +x-7

D. 3x^4-3x^{2} +5x-7

Now, let us evaluate the given expressions one by one.

(4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4

It is equation B.

So, (4x^3-4+ 7x)-(2x^3-x-8) is equivalent to B.

(-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7

It is equation D.

So, (-3x^2+x^4+x)+(2x^4-7+4x)  is equivalent to D.

(x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x

It is equation A.

So, (x^{2} -2x)(2x+3) is equivalent to A.

So, answer is:

B

D

A

8 0
3 years ago
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