The ship movement is an illustration of distance and bearing
The ship is 31.97 miles from its point of departure
<h3>The distance from the point of departure?</h3>
The given parameters are:
- Distance east = 40 milies
- Distance southwards = 70 miles
- Angle = 12 degrees
See attachment for the image of the above parameters
The distance (x) from the point of departure is then calculated using the following cosine function
a^2 = b^2 + c^2 - 2bc * cos(Ф)
So, we have:
x^2 = 40^2 + 70^2 - 2 * 40 * 70 * cos(12)
Evaluate the exponent and the product
x^2 = 6500 - 5477.63
Evaluate the difference
x^2 = 1022.37
Evaluate the exponent
x = 31.97
Hence, the ship is 31.97 miles from its point of departure
Read more about distance and bearing at:
brainly.com/question/24142612
Answer:
46 mph and 61 mph
Step-by-step explanation:
Distance=speed*time
Let speed of one bus be x and another x+15
After 3 hours
First bus would have traveled 3x while second bus 3(x+15)=3x+45
Total distance= 3x+3x+45=6x+45
6x+45=321
6x=321-45=276
x=276/6=46 mph
x+15=46+15=61 mph
Answer:product means the answer to a multiplication problem
Step-by-step explanation: you are welcome
Answer:
27
Step-by-step explanation:
220-4=216
216/8=27