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pashok25 [27]
3 years ago
12

These questions both go together if you answer them I'll give you brainliest !! :)

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer: the answer is 2.5

Step-by-step explanation:

I just did that

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Can somebody help me please ..
musickatia [10]

Answer: Red

Step-by-step explanation:

The y intercept is -2 so its either green or red

the slope is positive so its red

7 0
3 years ago
16 What is the percentage of 72<br> A)22.2%<br> B)2.22%<br> C)4.5%<br> D)45%
8_murik_8 [283]
16/72 = x/100
72x = 1600
/72      /72

<span> x = 22.222.....

Answer: Choice A</span>
5 0
3 years ago
Read 2 more answers
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
What is the factor for 30n-40
nikitadnepr [17]
Factor: 
<span>30n - 40 = 10(3n - 4)

hope it helps</span>
7 0
3 years ago
JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw
luda_lava [24]

i. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the 
3 0
3 years ago
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