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docker41 [41]
2 years ago
5

What is the value of x to the nearest tenth?

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
4 0

Answer:

35

Step-by-step explanation:

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considering the leading term of the polynomial function. what is the end behavior of the graph? describe the end behavior and pr
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The leading term of polynomial function is the the term contain highest degree so here in the given question leading term is  -3x^5

and leading coefficient is the coefficient of the term with greatest exponent -3

RULES for End behaviour

we have following four cases

CASE1: Even degree and positive leading coefficient

x\rightarrow -\infty      f(x)\rightarrow \infty

x\rightarrow \infty        f(x)\rightarrow \infty

CASE2: Even degree and negative leading coefficient

x\rightarrow -\infty        f(x)\rightarrow -\infty

x\rightarrow \infty           f(x)\rightarrow -\infty

CASE3: Odd degree and positive leading coefficient

x\rightarrow -\infty          f(x)\rightarrow -\infty

x\rightarrow \infty              f(x)\rightarrow \infty

CASE4: Odd degree and negative leading coefficient

x\rightarrow -\infty              x\rightarrow \infty  

x\rightarrow \infty                  f(x)\rightarrow -\infty


Here in the given case we have odd degree and negative leading coefficient

x\rightarrow -\infty              x\rightarrow -\infty  

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3 years ago
A large mixing tank initially contains 1000 gallons of water in which 40 pounds of salt have been dissolved. Another brine solut
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Answer:

If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt =  15 - 0.005A

Option C) dA/dt =  15 - 0.005A is the correction Answer

Step-by-step explanation:

Given the data in the question;

If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?

dA/dt = rate in - rate out

first we determine the rate in and rate out;

rate in = 3pound/gallon × 5gallons/min = 15 pound/min

rate out = A pounds/1000gallons × 5gallons/min  = 5Ag/1000pounds/min

= 0.005A pounds/min

so we substitute

dA/dt = rate in - rate out

dA/dt =  15 - 0.005A

Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt =  15 - 0.005A

Option C) dA/dt =  15 - 0.005A is the correction Answer

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Last question for today ✌
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Answer:

I think it is D

Step-by-step explanation:

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