Question

A triangular pyramid has an isosceles triangular base. The base edge of the triangular base is 10

Answer 1

Answer:

h=94.87

Step-by-step explanation:

1. Volume of pyramid formula:

$v=\frac{1}{3}*a^{2}*h$

$a=b*h$ Base Edge * Height of Pyramid

2. We have variables:

V = 480, Base Edge = 10, Height of Base = 16 (Inch)

3. Plug into formula + Rearrange:

$\frac{3V}{h} =(b*h)^{2} [b^{2} *h^{2} ]$

$\frac{3V*b^{2} }{h} =h^{2}$

$h^{2}=\frac{3*480*10^{2} }{16}$

$h=\sqrt{9000}$

h≅94.868