the length is 3W cm. THerefore, the perimeter is 2*(3W + W) = 8W = 56 So W = 7 cm.
Take the deritiivive
it is zero at pi/4 and it repeats at every pi
minimum at where slope goesfrom negative to positive
so at 5pi/4 and 13pi/4 so at every 2pi interval
evaluate origial at 5pi/4
=
=
or aprox 1.22509
It the x by the 5 then go around the town to see
The multiples of 8 are: 0, 8, 16, 24, 32, 40, 48, ...
The multiples of 10 are: 0, 10, 20, 30, 40, 50, ...
LCM(8, 10) = 40
LCM(x²y², x²y³) = x²y³
Therefore
<h3>LCM(8x²y², 10x²y³) = 40x²y³</h3>
Answer:
It is not a Type I error neither a Type II error.
Step-by-step explanation:
Let be the true mean match score. The null hypothesis is and the alternative hypothesis is (upper-tail alternative). When the test shows that the mean match score is more than 80 when actually is equal to 80 a Type I error is made. On the other hand, when the test shows that the mean match score is equal to 80 when actually is more than 80 a type II error is made. Therefore, when the test shows that the mean match score is more than 80 when the person does not actually have a fingerprint match, does not correspond to a Type I error neither to a Type II error.