In this case, we must analyze the question to find the solution.
Step 01:
equation one variable vs system of equations two variables = ?
Step 02:
In an equation with one variable, we must only apply the algebraic rules to find its value.
For systems of equations, we have different methods to solve them.
And it is possible to write the equations as a function of one variable, and then substitute in the other equation and thus find the solution.
Therefore, it is comparable to solving one variable equation.
That is the answer.
X*a = 244 is equation (1)
x+a = 2 is equation (2)
Solve equation (2) for 'a' to get
x+a = 2
a = 2-x
Call this equation (3)
We will plug equation (3) into equation (1)
x*a = 244
x*(a) = 244
x*(2-x) = 244
Notice how the 'a' is replaced with an expression in terms of x
Let's solve for x
x*(2-x) = 244
2x-x^2 = 244
x^2-2x+244 = 0
If we use the discriminant formula, d = b^2 - 4ac, then we find that...
d = b^2 - 4ac
d = (-2)^2 - 4*1*244
d = -972
indicating that there are no real number solutions to the equation x^2-2x+244 = 0
So this means that 'x' and 'a' in those two original equations are non real numbers. If you haven't learned about complex numbers yet, then the answer is simply "no solution". At this point you would stop here.
If you have learned about complex numbers, then the solution set is approximately
{x = 1 + 15.588i, a = 1 - 15.588i}
which can be found through the quadratic formula
Note: it's possible that there's a typo somewhere in the problem that your teacher gave you.
Answer:
4x +10
Step-by-step explanation:
-2(x-5) +6x
-2x +10 +6x
4x +10
