Answer:
The ball remain in air for 3.06 seconds.
Maximum height reached = 22.94 m
Explanation:
We have equation of motion v = u + at
At maximum height, final velocity, v =0 m/s
Initial velocity = 15 m/s
acceleration = -9.81 m/s²
Substituting
0 = 15 -9.81 t
t = 1.53 s
Time of flight = 2 x 1.53 = 3.06 s
The ball remain in air for 3.06 seconds.
We also have equation of motion v² = u² + 2as
At maximum height, final velocity, v =0 m/s
Initial velocity = 15 m/s
acceleration = -9.81 m/s²
Substituting
0² = 15² - 2 x 9.81 x s
s = 22.94 m
Maximum height reached = 22.94 m
