Question

Let f(x)=2x and g(x)=2x

Answer 1

Answer:

Rewrite (Lambert form):

$e^{\ln \left(2\right)\left(1-\left(-\frac{u}{\ln \left(2\right)}\right)\right)}\left(-\frac{u}{\ln \left(2\right)}\right)=1$

Simplify :

$-\frac{e^{\ln \left(2\right)+u}u}{\ln \left(2\right)}=1$

Solve:

$u=-2\ln \left(2\right),\:u=-1\cdot \ln \left(2\right)$

Result:

$x=2,\:x=1$

Hope this helped u :)

If this was too complicated I can edit it for you.