Answer:
C
Step-by-step explanation:
We want to determine the vertex of the quadratic equation:
Recall that the vertex is given by the formulas:
In this case, <em>a</em> = -1, <em>b</em> = 2, and <em>c</em> = 1.
Determine the <em>x-</em>coordinate of the vertex:
To determine the <em>y-</em>coordinate, evaluate the function at <em>x</em> = 1:
In conclusion, the vertex of the quadratic equation is (1, 2).
Hence, our answer is C.
Answer: What's the exponents?
Step-by-step explanation:
5.2+3.01=8.21
but then there's no exponents that you stated. So it would be 8.21x10^?
If the tens do have exponents above them, add them together.
I hope this answer helps you!
Answer:
I believe it would be true
-2=-x+x square-4
firstly regroup the equation
x square-2x+x-2=0
x square-x-2=0
multiply the first term by the last term.(I.e x square multiply by -2=-2x square)
product of factor = -2x 1
sum of factor= -2x+1(x)= -1
x square -2x+x-2=0
open the bracket:
x(x-2)+1(x-2)=0
x=1 or x=-2
Therefore; x=-1 or x=2
Y^2-9^2
(y-9)(y+9)
To see if its right:
y*y+y*9-9*y-9*9
y^2+9y-9y-81
y^2-9^2
