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2 years ago

Whats the answer 6+1

Mathematics

2 answers:

RSB [31]2 years ago

7 0

7
My. Homie is 7
I know this because I learned to add when Dr.Seuss taught me

Sergeeva-Olga [200]2 years ago

6 0

Answer:

Step-by-step explanation:

Add 1 to six and u get seven.

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What is the range of the function y = x2? all real numbers x ≥ 0 y ≥ 0

masya89 [10]

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Step-by-step explanation:

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2 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (

Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

$6, \, 27x^2, \, \frac{405x^4}{4}.$

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

$\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...$

So, for the given function y = 6 sec(3x), we get:

$y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...$

So, the first three nonzero terms in the Maclaurin series are:

$6, \, 27x^2, \, \frac{405x^4}{4}.$

6 0

2 years ago

A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r

Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

$P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5$

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, $n(S)=6$

Now, probability of rolling a 3 is given as:

$P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}$

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

$P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083$

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0

3 years ago