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3 years ago

11

Convert this fraction into a decimal.

2 answers:

ZanzabumX [31]3 years ago

6 0

Your answer is going to be 0.6

Elena L [17]3 years ago

3 0

The answer is 0.6 Explanation: Since it’s 6/10 the 6 goes n the tenths place.

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nignag [31]

Answer: 352

Step-by-step explanation:

3 0

3 years ago

Complete the explanation of how you would shade a model to show 2 x 2/3

Alekssandra [29.7K]

Answer:

B.

Step-by-step explanation:

3 0

3 years ago

Find the missing length for the right triangle described below. B = 21 ft, c=27 ft. Find side a. Round to the nearest whole numb

maksim [4K]

Answer:

16.97 ft

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Side B = 21 ft

Side c = 27 ft

As we know, formula for right triangle is as follows,

$a^{2} + b^{2} = c^{2}$

$a^{2} = c^{2} - b^{2}$

So, by putting the value in the formula, we get,

$a^{2} = 27^{2} - 21^{2}$

$a^{2}$ = 729 - 441

$a^{2}$ = 288

a = 16.97 ft

Hence, the length of the side for the right triangle is 16.97ft.

6 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

Lucy plans to spend between $50 and $60, inclusive, on packages of beads and packages of charms. If she buys 5 packages of beads

worty [1.4K]

She can buy maximum of $5$ packages while staying within her budget.

Minimum spending limit $=$ $ $50$ .

Maximum spending limit $=$ $ $60$ .

Cost of one package of beads $=$ $ $4.95$ .

Number of packages of beads bought $= 5$ .

Cost of one package of charms $=$ $ $6.55$ .

Let the number of packages of beads bought be $x$ .

$4.956 \times 5 + x \times 6.55 \geq 50$

$24.78+6.55x\geq 50$

$6.55x\geq 25.22$

$x\geq 3.85$

$4.956 \times 5 + x \times 6.55 \leq 60$

$24.78+6.55x\leq 60$

$6.55x\leq 35.22$

$x\leq 5.38$

So, she can buy maximum of $5$ packages while staying within her budget.

Learn more about solving inequalities here:

brainly.com/question/12189350?referrer=searchResults

7 0

2 years ago