If x=(2a-3b),y=(2a+3b)and z=9bsquare -4absquare,show that xy+z=0
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Answer:
Step-by-step explanation:
volume = area of base * height = area of base * 9 = 72
-> area of base = 72/9 = 8
let a,b,c be the length of sides of isosceles right triangle base
we have a = b and a*b/2 = 8 ft2
-> a*a/2 = 8ft2
-> a*a = 16
-> a=4ft=b
have c^2 = a^2 + b^2 = 16 +16 = 32
-> c = = 5.656 ft
Since i dont know that is DF, i calculate both a,b and c
