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Ray Of Light [21]
3 years ago
10

All things algebra unit 7 homework 6 questions 7 and 8​

Mathematics
1 answer:
maxonik [38]3 years ago
6 0
3/3 the answer but i have to ask a question so please give this a good rating or something
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A(x)= 3m(x)+4 in standard form
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a(x)= 3mx+4

Step-by-step explanation:

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2 years ago
Which decimal is equivalent to forty and seventy six thousands ? a.40.076 b 40.76 C 47.006 D 47.06​
krek1111 [17]

Answer:

A. 40.076

Step-by-step explanation:

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7 0
3 years ago
"a pollster wishes to estimate the number of left-handed scientists. how large of a sample is needed in order to be 98% confiden
nadezda [96]
The sample size should be 250.

Our margin of error is 4%, or 0.04.  We use the formula

\text{ME}=z\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

To find the z-score:
Convert 98% to a decimal:  0.98
Subtract from 1:  1-0.98 = 0.02
Divide both sides by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value has a z-score of approximately 2.33.  Using this, our margin of error and our proportion, we have:

0.04=2.33\sqrt{\frac{0.08(1-0.08)}{n}}&#10;\\&#10;\\0.04=2.33\sqrt{\frac{0.08(0.92)}{n}}

Divide both sides by 2.33:
\frac{0.04}{2.33}=\sqrt{\frac{0.08(0.92)}{n}}

Square both sides:
(\frac{0.04}{2.33})^2=\frac{0.08(0.92)}{n}

Multiply both sides by n:
(\frac{0.04}{2.33})^2n=0.08(0.92)

Divide both sides to isolate n:
\frac{0.08(0.92)}{(\frac{0.04}{2.33})^2}=n&#10;\\&#10;\\249.73=n&#10;\\n\approx 250
4 0
3 years ago
7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and
Juliette [100K]

Answer:

A) JK and AB =

[tex] \boxed{( \theta) = \f{12}{( \theta)} } So, =》 \dfrac{10}{5} = \dfrac{1}{ \( \theta) } =》 \( \theta) = \dfrac{5}{2}[/tex]

B) AABC

[tex] \boxed{( \theta) = {1}{( \theta)} } So, 23}{-18=\\Ans } \boxed

C) AABM:

[tex] e \fbox{: } The value of k for which \sin(jm) = \cos(x) is \dfrac{\p}{2} ans[/tex]

----------

3 0
3 years ago
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