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Vika [28.1K]
3 years ago
12

Could anyone that has taken or is currently taking math 3 go look at my profile pls? I posted a question and got a fake answer.

I'll give you brainliest pls help .-_.-
Mathematics
1 answer:
kozerog [31]3 years ago
3 0

Answer:

I tried

Step-by-step explanation:

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Listed in the Item Bank are individual steps that need to be ordered.
Sav [38]

Answer: - 3.75  <  - 0.55  <  - 12  <  - 15  <  - 0.03

Step-by-step explanation: that is the answer i just did it on my computer good luck!

6 0
2 years ago
Complete the paragraph below. The standard deviation is used in conjunction with the​ ______ to numerically describe distributio
Bumek [7]

Answer:

The standard deviation is used in conjunction with the​ mean to numerically describe distributions that are bell shaped. The​ mean measures the center of the​ distribution, while the standard deviation measures the​ spread of the distribution.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

The mean is the average value of the measures while the standard deviation measures how spread the measures are from the mean. So

The standard deviation is used in conjunction with the​ mean to numerically describe distributions that are bell shaped. The​ mean measures the center of the​ distribution, while the standard deviation measures the​ spread of the distribution.

4 0
3 years ago
Simplify the expression.
denis23 [38]

Answer:

option d

Step-by-step explanation:

\sf \boxed{a^m*a^n = a^{m+n}\\\\}

\sf \left(\frac{m^{-1}m^{5}}{m^{-2}} \right)^{-3} =\left(\dfrac{m^{-1+5}}{m^{-2}}\right)^{-3}

                 \sf = \left(\dfrac{m^4}{m^{-2}}\right)^{-3}\\\\

\boxed{\dfrac{a^{m}}{a^{n}}=a^{m+n}}

                    \sf = \left(m^{4-[-2]}\right)^{-3}\\\\      =\left(m^{4+2}\right)^{-3}\\\\       = \left(m^6\right)^{-3}\\\\

\boxed{(a^{m})^n=a^{m*n}}

                    \sf= m^{6*(-3)}\\\\    = m^{-18}

\boxed{a^{-m}=\dfrac{1}{a^m}}

                    \sf=\dfrac{1}{m^{18}}

8 0
2 years ago
(-2 1/2) to the second power
trapecia [35]

Answer:

6.25

Step-by-step explanation:

(-2\frac{1}{2})^2\\\\(-\frac{5}{2} )^2\\\\(\frac{5}{2})^2\\\\\frac{5^2}{2^2}\\\\\frac{25}{4}\\\\\boxed{6\frac{1}{4}}\text{ or } 6.25

Hope this helps.

5 0
3 years ago
Read 2 more answers
In a recent survey of 974 voters, 724 indicated that they were in favor of a new city park, while the other 250 voters said that
Lesechka [4]

10, 267

the fraction of voters opposed from the survey = \frac{250}{974}

Assuming this fraction as a basis then the predicted number against will be

40, 000 × \frac{250}{974} = 10, 267 ( nearest while number )


7 0
4 years ago
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