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SIZIF [17.4K]
4 years ago
9

Plz help 25 pointsss

Mathematics
1 answer:
Natasha2012 [34]4 years ago
4 0

Answer:

Ok

Step-by-step explanation:

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What is 10/8 in simplest form
aliya0001 [1]
10/8 in simplest form:

First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.

Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8

We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.

Second, divide the numerator and the denominator by the GCF (2).
10 \div 2 = 5  \\ 8 \div 2 = 4

Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get: \frac{5}{4}

Answer in fraction form: \fbox {5/4}
Answer in decimal form: \fbox {1.25}
Answer in mixed number form: \fbox {1 1/4}
4 0
3 years ago
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Why does the author of "The Think Tank" include Shumaker's admission that he did not think that Azy would be the fastest learner
galben [10]
The answer is C. to show that animals can even surprise experts with their capacity to learn
4 0
3 years ago
Points A, B, and C are collinear. Point B is between A and C, AC=15a-5 , AB=10a+6, and BC=3a+11. Find AB
sdas [7]

Answer:

I bet you're smarter than me so you can figure it out

Step-by-step explanation:

good thing you aint like me

7 0
3 years ago
Which expression is equal to 0?<br> A) 2 + 0 + 3<br> B) 2x0x3<br> C) 1 + (0 x 2)<br> D) (1 x 2) + 0
GrogVix [38]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
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E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe
timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5

So,

EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1

And

GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)

Now

FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\   ..... (2)

Solving (1) and (2)

b = - 2 ,

a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6

3 0
3 years ago
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