Answer: 1.23 M Ca
Explanation:
Molarity is moles of solute/volume (only liters) of solution
Convert mL to L
To do that divide by 1000
Therefore, 2.34 mol/1.86 L
Answer is 1.23 M Ca
The answer would be D. Good luck my dude
Answer:
n of krypton = 1.23 mol.
The no. of moles will not be changed, if the gas is either argon or krypton.
Explanation:
- The no. of moles of a gas (n) can be calculated by the general gas law of ideal gases: <em>PV = nRT</em>,
Where, P is the pressure of the gas in atm (P = 6.0 atm).
V is the volume of the gas container in L (V = 5.0 L).
n is the no. of moles of the gas.
R is the general gas constant (R = 0.082 L.atm/mol.K).
T is the temperature of the gas in K (T = 25.0°C + 273 = 298.0 K).
<em>∴ n = PV/RT </em>= (6.0 atm)(5.0 L)/(0.082 L.atm/mol.K)(298.0 K) = 1.228 mol = <em>1.23 mol.</em>
The no. of moles will not be changed, if the gas is either argon or krypton because it does not depend on the type of the gas.
Answer:
47.2%
Explanation:
Judging from the question given, the theoretical yield is 10g because the student had already made his/her calculation and was expecting to get the same result at the end of the experiment. But he could only get 4.72g from the experiment.
Now, The percentage yield can be obtain as follows
Experimental yield = 4.72g.
Theoretical yield = 10g
%yield = Experimental yield /Theoretical yield x100
% yield = 4.72/10 x100
%yield = 47.2%
Therefore, the percentage yield of the experiment is 47.2%
The complete question is; copper (i) ions in aqueous solutions react with NH3(aq) according to;
Cu +2NH3 = Cu(NH3)2 Kt= 6.3 × 10^10
Calculate K
Cu + 2NH3 = Cu(NH3)2
kf = 6.3 ×10^10
The ksp for CuBr = Cu + Br = 6.3 × 10^-9
For the reaction; CuBr +2NH3 = Cu(NH3)2 + Br to calculate K?
K = (6.3 × 10^10)(6.3×10^-9)
Thus K is 396.9