Where are the quadratic equations?
It is 120 ways, surprisingly
so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
Answer:
6 clown fish and 4 angel fish
Step-by-step explanation:
<u>lets say he bought 8 clown fish. </u>
12*8 = 96
the last 4 dollars wont be used.
<u>lets say he bought 7 clown fish-</u>
12*7 = 84
100 - 84 = 16. 16 is not a multiple of 7.
<u>lets say he bought 6 clown fish,</u>
12*6 = 72
100 - 72 = 28
28/7 = 4
If David has $100 dollars to spend and wants to spend every dollar, he can buy 6 clown fish and 4 angel fish.
So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}
Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)
Now distribute the 9:
567 + 108 + 81
And finally solve as a normal addition problem:
567 + 108 + 81= 756
So, the answer is 756.
I hope this helps:)
