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julia-pushkina [17]
2 years ago
9

If you know that​ R' (20)=50 and​ R''(20)=-4, approximate​ R'(24)

Mathematics
1 answer:
vladimir1956 [14]2 years ago
4 0

Approximate <em>R'</em> by using a linear approximation: for <em>x</em> close enough to 24, you have

<em>R'(x)</em> ≈ <em>L(x)</em> = <em>R' </em>(20) + <em>R''</em> (20) (<em>x</em> - 20)

Then

<em>R'</em> (24) ≈ <em>R'</em> (20) + <em>R''</em> (20) (24 - 20) = -4 + 50 (24 - 20) = 196

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have you baseball card collection got what animals ruined you bought 11 cards to replace some that were lost how many did you be
UkoKoshka [18]
24 (you new amount) - 11 (new cards) = 13 cards to begin with
6 0
2 years ago
Charlie is watching hot air balloons. balloon a has risen at a 50° angle. balloon b has risen at a 78° angle. if the distance fr
AfilCa [17]

The distance from Balloon A to Balloon B, d ≈ 1,052 feet

What is distance ?

  • Distance is defined to be the magnitude or size of displacement between two positions.
  • Note that the distance between two positions is not the same as the distance traveled between them.
  • Distance traveled is the total length of the path traveled between two positions. Distance traveled is not a vector.

The given parameters are;

The angle at which Balloon A rises, x° = 50° above horizontal

The angle at which Balloon B rises, y° = 78° above horizontal

The (vertical) distance of Balloon A to the ground, h = 1,000 ft.

The required parameter;

The distance from Balloon A to Balloon B, d

We find the distances of the balloons from Charlie and the angle between the balloon strings, θ, then apply cosine rule

Let,

The height of the balloon strings are equal

The distance of Balloon A to the ground, h₁ = The distance of Balloon B to the ground, h₂ = 1,000 ft.

The distance of the Balloon A  from Charlie, l₁, is given as follows;

l₁ × sin(x°) = h₁

∴ l₁ = h₁/(sin(x°))

Which gives;

l₁ = 1,000 ft./(sin(50°)) ≈ 1,305.41 ft.

l₁ ≈ 1,305.41 ft.

For Balloon B, we get;

h₁ = h₂ = 1,000 ft.

∴ l₂ = 1,000 ft./(sin(78°)) ≈ 1,022.34 ft.

l₂ ≈ 1,022.34 ft

The angle between the balloon strings, θ = 180° - (x° + y°)

∴ θ = 180° - (50° + 78°) = 52°

The angle between the balloon strings, θ = 52°

By cosine rule, we have;

d = √(l₁² + l₂² - 2 × l₁ × l₂ × cos(θ))

∴ d = √(1,305.41² + 1,022.34² - 2 × 1,305.41×1,022.34 × cos(52°)) ≈ 1,052 feet

Therefore, the distance from Balloon A to Balloon B, d ≈ 1,052 feet

Learn more about distance

brainly.com/question/15172156

#SPJ4

7 0
2 years ago
Can u guys PLEASE answer this question ASAP.
Andrej [43]

Answer:

  • 1. Interest: $166.67

           Principal: $6,166.67

  • 2. Interest: $200.00

            Principal: $5,200.00

Explanation:

<u><em>1. $6000 for 50 days at 20% p.a</em></u>

<u><em></em></u>

In 20% pa, pa means "per annum", i.e. "per year".

Assume simple interest:

  • Principal: $6,000
  • interest: 20% pa
  • time = 50 days

Interest:

  • Interest = Principal × number of days × annual rate / 360

  • Interest = $6,000 × 50 × 20% / 360 = $166.67

Principal = principal + interest = $6,000 + $166.67 = $6,166.67

<u><em></em></u>

<u><em>2. $5000 for 5 months at 0.8% per month</em></u>

Assume, again, simple interest.

  • Principal: $5,000
  • interest: 0.80% per month
  • time = 5 months

Interest:

  • Interest = Principal × number of months × montly rate

  • Interest = $5,000 × 5 × 0.80%  = $200.00

Principal = principal + interest = $5,000 + $200.00 = $5,200

You can see that the accrued interests depend on the principal, the interest rate, and the time.

8 0
3 years ago
Write each mixed number as a decimal.<br> 1.) 4 1/5 <br> 2.) 12 14/15<br> 3.) 5 5/32
bezimeni [28]
I showed you how to do it in the picture.

<span>Answers:
1.) 4 1/5 = 4.22.) 12 14/15 = 12.93 (3 is repeating so draw a line on top of just the 3)<span>3.) 5 5/32 = 5.156 (the 56 is repeating so draw a line on top of just the 56)

Hope this helps you the </span><span>way you want! </span><span>-Jabba</span></span>

6 0
2 years ago
Read 2 more answers
NEED HELP ASAP!!!
azamat
The answer is B f(x)= -3(x+1)^2+2
6 0
3 years ago
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