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geniusboy [140]
3 years ago
11

What are like arms surrounding all the other code blocks?

Computers and Technology
2 answers:
liq [111]3 years ago
4 0

Answer:

Parenthesis

Explanation:

I code

Leni [432]3 years ago
3 0

Answer:

Its curly braces.

Your welcome!

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Write a program that gets a list of integers from input, and outputs the integers in ascending order (lowest to highest). The fi
Travka [436]

Answer:

Explanation:

Since no programming language is stated, I'll use Microsoft Visual C# in answering this question.

// C# program sort an array in ascending order

using System;

class SortingArray {

int n; //number of array elements

int [] numbers; //Array declaration

public static void Main() {

n = Convert.ToInt32(Console.ReadLine());

numbers = new int[n];

for(int i = 0; i<n; I++)

{

numbers [n] = Convert.ToInt32(Console.ReadLine());

}

SortArray();

foreach(int value in numbers)

{

Console.Write(value + " ");

}

}

void SortArray()

{

int temp;

// traverse 0 to array length

for (int i = 0; i < numbers.Length - 1; i++)

// traverse i+1 to array length

for (int j = i + 1; j < numbers.Length; j++){

// compare array element with all next element

if (numbers[i] < numbers[j])

{

temp = numbers[i];

numbers[i] = numbers[j];

numbers[j] = temp;

}

}

}

5 0
4 years ago
A _____ is a machine that changes information from one form into another.
gavmur [86]
The answer would be computer
5 0
3 years ago
SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R
adoni [48]

Answer:

Check the explanation

Explanation:

Player 1 Coin

Player 2 Coin

Player 1

Player 2

Round

Count at

Count at

Player

Player

Coin

Coin

Number

Beginning of

Beginning of

1

2

Outcome

Count at

Count at

Round

Round

Spends

Spends

End of

End of

Round

Round

Off-by-

one,

10 - 1

10

10

2

player 2

10 - 2

+

= 8

1

gains 1

= 10

coin

Same,

10 - 2

2

8

10

2

2

player 2

-

gains 1

6

+

=

1

=

9

coin

Off-by-

two,

6 - 1

+

3

6

9

3

player 1

2

9 - 3

gains 2

=

=

7

6

coins

Same,

4

7

6

2

2

player 2

7 - 2

6 - 2+

gains 1

=

5

=

coin

5

Kindly check the attached image below to see the well arranged table to solve the above question.

4 0
3 years ago
__________ is a Microsoft software development tool that developers can use to write multimedia applications
ohaa [14]

answer:

DirectX.    

hopefully this is helpful.

6 0
3 years ago
C++
daser333 [38]

#include<iostream>

#include <fstream>

#include <vector>

#include <string>

#include "StatePair.h"

using namespace std;

int main() {

ifstream inFS;

int zip;

int population;

string abbrev;

string state;

unsigned int i;

vector<StatePair <int, string>> zipCodeState;

vector<StatePair<string, string>> abbrevState;

vector<StatePair<string, int>> statePopulation;

inFS.open("zip_code_state.txt");

if (!inFS.is_open()) {

    cout << "Could not open file zip_code_state.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <int, string> temp;

    inFS >> zip;

    if (!inFS.fail()) {

        temp.SetKey(zip);

    }

    inFS >> abbrev;

    if (!inFS.fail()) {

        temp.SetValue(abbrev);

    }

    zipCodeState.push_back(temp);

}

inFS.close();

inFS.open("abbreviation_state.txt");

if (!inFS.is_open()) {

    cout << "Could not open file abbreviation_state.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <string, string> temp;

    inFS >> abbrev;

    if (!inFS.fail()) {

        temp.SetKey(abbrev);

    }

    getline(inFS, state);

    getline(inFS, state);

    state = state.substr(0, state.size()-1);

    if (!inFS.fail()) {

        temp.SetValue(state);

    }

    abbrevState.push_back(temp);

}

inFS.close();

inFS.open("state_population.txt");

if (!inFS.is_open()) {

    cout << "Could not open file state_population.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <string, int> temp;

    getline(inFS, state);

    state = state.substr(0, state.size()-1);

    if (!inFS.fail()) {

        temp.SetKey(state);

    }

    inFS >> population;

    if (!inFS.fail()) {

        temp.SetValue(population);

    }

    getline(inFS, state);

    statePopulation.push_back(temp);

}

inFS.close();

cin >> zip;

for (i = 0; i < zipCodeState.size(); ++i) {

 }

for (i = 0; i < abbrevState.size(); ++i) {

 }

for (i = 0; i < statePopulation.size(); ++i) {

}

}

Statepair.h

#ifndef STATEPAIR

#define STATEPAIR

#include <iostream>

using namespace std;

template<typename T1, typename T2>

class StatePair {

private:

T1 key;

T2 value;

public:

StatePair()

{}

void SetKey(T1 key)

{

this->key = key;

}

void SetValue(T2 value)

{

this->value = value;

}

T1 GetKey() { return key;}

T2 GetValue() { return value;}

void PrintInfo()

{

cout<<key<<" : "<<value<<endl;

}

};

3 0
2 years ago
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