Point slope form
y-y1=m(x-x1)
slope=m
a point is (x1,y1)

slope=(y2-y1)/(x2-x1)
given
(-6,4) and (2,0)
slope=(0-4)/(2-(-6))=-4/(2+6)=-4/8=-1/2

a point is (-6,4)
x1=-6
y1=4

y-4=-1/2(x+6)
not listed

5 0

3 years ago

32 = 2m - 6 Plz Help! This is due and I did not learn this because I was absent that day! Help me Plz! 14 points!

san4es73 [151]

The answer would be m=24

Please can i have a brainlier

5 0

3 years ago

Read 2 more answers

If u(x)=-2x²+3 and v(x)=1/x, what is the range of (u ° v)(x)?

Ludmilka [50]

$u(x)=-2x^2+3\\\\v(x)=\dfrac{1}{x}\\\\(u\ \circ\ v)(x)=-2\left(\dfrac{1}{x}\right)^2+3=-2\left(\dfrac{1}{x^2}\right)+3=-\dfrac{1}{x^2}+3\\\\\text{The range of}\ y=\dfrac{1}{x^2}\ \text{is all positive real numbers.}\\\\\text{The range of}\ y=-\dfrac{1}{x^2}\ \text{is all negative real numbers.}\\\\\text{The range of }\ (u\ \circ\ v)(x)=-\dfrac{1}{x^2}+3\ is\ (-\infty,\ 3)$

6 0

4 years ago

Read 2 more answers

Is this relation a function?<br> {(-8,6), (-5,-2), (0,5), (1,-2), (0,-8)}

creativ13 [48]

C no because 0 repeats you can’t have 2 of the same inputs

5 0

3 years ago