First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at 
, the equation will contain a 
term.
If we start with 
we have a parabola, concave down, with vertex at and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have
Now we only have to fix the fact that this parabola doesn't land at 
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
such that:
Plugging these values gets us
As you can see in the attached figure, the parabola we get satisfies all the requests.
Use photos math it helps alot
I will show you how to do the first one.....we are finding the GCF...the largest number that goes into each number (same for variables)
1.) 20yx , 80x³ ( factor each number and variable)
20 = 2, 4, 5, 10, 20
y = y
x = x
80 = 2, 4, 5, 8, 10, 16, 20, 40, 80
x³ = x, x, x
what is the largest number that 20 and 80 have in common? 20...
how about the variables? x
so, the Greatest Common Factor (GCF is 20x)
Answer:
The Answer is D
Step-by-step explanation:
, we have
