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almond37 [142]
3 years ago
10

How can you know if this equation is true? 1/2 + 3/8 = 4/10 = 2/5

Mathematics
1 answer:
romanna [79]3 years ago
3 0

Answer:

<h2>2. Because 25<12, this equation can not be true.</h2>

Step-by-step explanation:

I just solved the equation and 1/2 + 3/8 = 7/8 or 87.5%.

4/10 equals 40%.

Since these two do not sync up, the equation must be false and 2 is the only answer saying the equation is false.

I'm always happy to help :)

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Question 19
Otrada [13]

Answer:

The slope is -1/3

4 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

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The sum of the parallelogram is 22 because I did the test
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2 years ago
What is the area of the given circle in Terms of Pi?
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I think it would be 27.38ᴹ2
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Read 2 more answers
What is 9 + 10=.........
Paladinen [302]
I hope this helps you





9+9+1



9 (1+1)+1


9.2+1


18+1


19
8 0
3 years ago
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