I think we must use two numbers which have two digits and one of them must be one digited number.If we try it we can say our numbers are xy,ab and c.
xy + ab + c = 50
10x+y+10a+b+c = 50
10(x+a) + y+b+c = 50
Think about y+b+c. Maximum it can be 5+4+3 = 12 but it can't because there is a number which is multiple of 10.So it can be 10 maximum and x+a must be 4.
We can only use 1+3. 40 + y+b+c = 50 , y+b+c = 10. And other numbers are 2+4+5 = 11. 10 doesn't equal to 11 and it says there isn't any solution for this problem :)
Algebra Examples
Popular Problems Algebra Divide (x^3-125)/(x-5)
x
3
−
125
x
−
5
x
3
-
125
x
-
5
Simplify the numerator.
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(
x
−
5
)
(
x
2
+
5
x
+
25
)
x
−
5
(
x
-
5
)
(
x
2
+
5
x
+
25
)
x
-
5
Reduce the expression by cancelling the common factors.
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x
2
+
5
x
+
25
Answer:
600
Step-by-step explanation:
if SP>CP,
It is profit [SP - CP = Profit]
if CP>SP,
It is loss [CP - SP = Loss]
Here in the question CP>SP so,
loss = CP - SP
=2500 - 1900
= 600
Answer: 12
Step-by-step explanation:
Answer: 1) c 2) d
<u>Step-by-step explanation:</u>
Use Pythagorean Theorem to find the hypotenuse (r): x² + y² = r²
Given: x = 2, y = 6
2² + 6² = r²
4 + 36 = r²
40 = r²
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