Question

The function f(x) is a quadratic function and the zeros of f(x) are -2 and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the quadratic polynomial in standard form.​

Answer 1

Answer:

The function f(x) is a quadratic function and the zeros of f(x) are -2 and 6. Assume the leading coefficient of f(x) is 1.

(x+2) and (x-6) are the factors of f(x)

$f(x) = (x + 2)(x - 6) \\ = {x}^{2} - 6x + 2x - 12 \\ = \boxed{{x}^{2} - 4x - 12}$

(x²-4x-12) is the right answer.

Answer 2

Step-by-step explanation:

Since the zeroes of f(x) are -2 and 6,

(x + 2) and (x - 6) are factors of f(x).

=> f(x) = (x + 2)(x - 6) = x² - 4x - 12.