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ZanzabumX [31]
2 years ago
15

Water lilies are often used to decorate ponds, as shown in the photo. But they are also famous for their unusual growth pattern!

Mathematics
1 answer:
aniked [119]2 years ago
4 0

Answer:

what is the question

pls mark me as brainlist

Thank you for the points

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Is 7/20 and 0.07 equivalent numbers
IceJOKER [234]
\frac{7}{20}=0.35 \\ 
 \\  \frac{7}{100}=0.07 \\ 
 \\ Solution: No \ they \ are \ not \ equivalent \ fractions \\
7 0
3 years ago
Read 2 more answers
How can we write x+x+5+5 in 2 different ways​
coldgirl [10]

Answer:

x + 5 + x + 5

5 + 5 + x + x

Step-by-step explanation:

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2 years ago
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2/x-1=3/3x-3+1/6<br> Please solve for x
sweet [91]

Answer:

1y

Step-by-step explanation:

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3 years ago
HELP PLS PLS I BEG U GEOMETRY AREA OF SECTOR
MAVERICK [17]

Answer:

The area of shaded sector

Formula A = (θ / 360°) × πr²

θ=360°-140°=220°

r=18yd

We have A=(220/360)×3.14×(18)²

=621.72yd²

Area of sector is621.72yd².

6 0
2 years ago
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-x^2+50=25 solve the equation
Andru [333]

Answer:

Two solutions were found :

x = 5

x = -5

Step-by-step explanation:

Step  1  :

Trying to factor as a Difference of Squares :

1.1      Factoring:  25-x2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  25  is the square of  5

Check :  x2  is the square of  x1

Factorization is :       (5 + x)  •  (5 - x)

Equation at the end of step  1  :

 (x + 5) • (5 - x)  = 0

Step  2  :

Theory - Roots of a product :

2.1    A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2      Solve  :    x+5 = 0

Subtract  5  from both sides of the equation :

                     x = -5

Solving a Single Variable Equation :

2.3      Solve  :    -x+5 = 0

Subtract  5  from both sides of the equation :

                     -x = -5

Multiply both sides of the equation by (-1) :  x = 5

Two solutions were found :

x = 5

x = -5

Processing ends successfully

plz mark me as brainliest :)

6 0
3 years ago
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