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3 years ago

Where are the points for Y=-x^2+160x-5000

1 answer:

4 0

None are given. You have to invent your own points that satisfy the given equation.

Examples: If x = 0, y = -5000 => (0,-5000)
If x = 2, y = -(2)^2 + 160(2) - 5000 = 4 + 320 - 5000 => (2, -4676)

and so on. Find as many such points as you want, using the same approach.

You might be interested in

Solve the equation 5.5(x-3)=17+10.5

sveticcg [70]

Answer:

x= 8

Step-by-step explanation:

5.5(x-3)=17+10.5

5.5x - 16.5= 27.5

5.5x= 44

x= 8

8 0

2 years ago

Read 2 more answers

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0

3 years ago

Write the following expression in terms of 2 and simplify 8V-64 Answer

Sholpan [36]

Answer:

4V-32

If is was wrong then don't report on me just tell me and I will automatic fix it for you

5 0

3 years ago

34. Lora is thinking of a number. It is less than 50 It is a 2-digit number. 3 is a factor of this number. The sum of its digits

-Dominant- [34]

Answer:

Step-by-step explanation:

The number is between 10 and 49

The number is divisible by 3

Let the 10s digit = x

Let the units digit = y

1/3 * (10x + y) = x + y multiply both sides by 3

10x + y = 3(x +y) remove the brackets.

10x +y = 3x + 3y Subtract 3x from both sides

10x - 3x + y = 3y Combine\

7x + y = 3y Subtract y from both sides.

7x = 3y - y Combine

7x = 2y

x can't be very big. Even taking 1/3 will get out of range is you use 6.

Also x should be an even number. The units digit cannot have a fraction in it.

Try making x = 2

7*2 = 2*y

14 = 2y Divide by 2

14/2 = y

y = 7

So the number is possibly 27. Let's check it out.

The number is between and includes 10 and 49. 27 is between these two endpoints.
27 is divisible by 3
1/3(27) = sum of digits
9 = (2 + 7)

All of the conditions are met. It's B

8 0

2 years ago

It's a ven dyagram question pls help

slamgirl [31]

Answer:

a) A U B = {21,23,24,25,27,29,30,31 }

b) A n C = {24,30}

Step-by-step explanation:

A {21,24,27,30}

B {21,23,25,27,29,31}

C {20,22,24,26,28,30,32}

a) A U B = {21,23,24,25,27,29,30,31 }

b) A n C = {24,30}

5 0

3 years ago