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madam [21]
3 years ago
10

Suppose a group of 12 students consists of five freshmen and seven sophomores. How many six-student teams can be chosen that con

sist of three freshmen and three sophomores? Give your answer as an integer.
Mathematics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

350

Step-by-step explanation:

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Murrr4er [49]

35 minutes for 5.25$


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3 years ago
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3 points lie on an xy plane, with each point representing where a particular person lives. Amy lives at point (2,3); Brian lives
geniusboy [140]
The equidistant point for all three, will be the "centroid" of their triangular locations
thus \bf \textit{Centroid of a Triangle}
\begin{array}{llll}
Amy
\begin{array}{llll}
(2,3)\\
x_1,y_1
\end{array}\quad Brian
\begin{array}{llll}
(0,7)\\
x_2,y_2
\end{array}\quad Claire
\begin{array}{llll}
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x_3,y_3
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6 0
3 years ago
Math HELP PLEASEE URGENT NOWWWWWW MATH!!!!
Viefleur [7K]

Answer:

A

Step-by-step explanation:

Answer is the first choice. you can tell by the notation.

5 0
3 years ago
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Ax-4y=-1. (6,1) find coefficient write complete equation
Rom4ik [11]
I think the answer is a=2
7 0
3 years ago
All my points to whoever can solve this
tankabanditka [31]

Answer:

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i

Step-by-step explanation:

5z^2−9z=−7z−5

We need to get all the terms on one side (set the right side equal to zero)

Add 7z to each side

5z^2−9z+7z=−7z+7z−5

5z^2−2z=−5

Add 5 to each side

5z^2−2z+5=−5 +5

5z^2−2z+5=0

This is in the form

az^2 +bz+c = 0 so we can use the quadratic formula

where a = 5   b = -2  and c = 5

-b± sqrt(b^2-4ac)

-------------------------

  2a

-(-2)± sqrt((-2)^2-4(5)5)

-------------------------

  2(5)

2± sqrt(4-100)

-------------------------

10


2± sqrt(-96)

-------------------------

10

2± sqrt(16)sqrt(-1) sqrt(6)

-------------------------

10

2± 4i sqrt(6)

-------------------------

10

1/5 ± 2/5 i sqrt(6)

Splitting the ±

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i


3 0
3 years ago
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