Answer:
a. answer to a can be found in the attached file
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
Step-by-step explanation:
"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
a. Find the probability tree as attached below
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
Answer:
The answer is 76.
Step-by-step explanation:
≅ means to be equal to.
☆Angle DGE ≅ EGF.
Therefore, 3x + 8 = 5x - 12
☆Let's solve that equation.

We found the value of x which is 10.
☆Let's Now plug in.

and the other:

☆They asked for what the angle of DGF measured. So we would have to add both sides

☆The answer is 76
The slope-intercept form:

m - slope
b - y-intercept
We have m = 2 and b = 3. Substitute:

Answer:
The dog weighs 16 pounds, while the cat weighs 8 pounds
Step-by-step explanation:
Let's call the weight of the dog d, and the weight of the cat c.
d+c=24
d=2c
Substitute the second equation into the first:
(2c)+c=24
3c=24
c=8
d=24-8=16
Hope this helps!
Step-by-step explanation:
<em>Given</em>
<em>We </em><em>know </em><em>that </em><em>in </em><em>a </em><em>parallelogram </em><em>opposite </em><em>angles </em><em>are </em><em>equal</em><em>. </em><em>So </em>
<em>1st </em><em>and </em><em>3rd </em><em>angles </em><em>=</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em>
<em>Let </em><em>2nd </em><em>and </em><em>4th </em><em>angles </em><em>=</em><em> </em><em>x</em>
<em>Now</em>
<em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>(</em><em> </em><em>Being </em><em>sum </em><em>of </em><em>angles </em><em>of </em><em>parallelogram</em><em>) </em>
<em>2</em><em>3</em><em>6</em><em>°</em><em> </em><em>+</em><em> </em><em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em>
<em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>2</em><em>3</em><em>6</em><em>°</em>
<em>2x </em><em>=</em><em> </em><em>1</em><em>2</em><em>4</em><em>°</em>
<em>Therefore </em><em>x </em><em>=</em><em> </em><em>6</em><em>2</em><em>°</em>
<em>Now </em><em>the </em><em>measure </em><em>of </em><em>other </em><em>all </em><em>angles </em>
<em>118</em><em>°</em><em> </em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em><em> </em><em>,</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em>