The answer is 52
x - the number of students in a bus
4 + 9x = 472
9x = 472 - 4
9x = 468
x = 468 / 9
x = 52
Answer: The quotient is (x-2).
Step-by-step explanation:
Since we have given that
![f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}](https://tex.z-dn.net/?f=f%28x%29%3D%28x%5E3%2B3x%5E2-4x-12%29%5C%5C%5C%5Cand%5C%5C%5C%5Cg%28x%29%3Dx%5E2%2B5x%2B6%5C%5C%5C%5CSo%2C%5C%20%5Cfrac%7B%5Cleft%28x%5E3%2B3x%5E2-4x-12%5Cright%29%7D%7B%5Cleft%28x%5E2%2B5x%2B6%5Cright%29%7D)
Now, we have to find the quotient of the above expression.
So, here we go:
![Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)](https://tex.z-dn.net/?f=Factorise%5C%20%28x%5E3%2B3x%5E2-4x-12%29%5C%5C%5C%5C%3D%5Cleft%28x%5E3%2B3x%5E2%5Cright%29%2B%5Cleft%28-4x-12%5Cright%29%5C%5C%5C%5C%3D-4%5Cleft%28x%2B3%5Cright%29%2Bx%5E2%5Cleft%28x%2B3%5Cright%29%5C%5C%5C%5C%3D%5Cleft%28x%2B3%5Cright%29%5Cleft%28x%5E2-4%5Cright%29)
Now, we will divide the above simplest form with g(x):
![\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%28x%2B3%5Cright%29%5Cleft%28x%5E2-4%5Cright%29%7D%7B%5Cleft%28x%2B2%5Cright%29%5Cleft%28x%2B3%5Cright%29%7D%5C%5C%5C%5C%3D%5Cfrac%7Bx%5E2-4%7D%7Bx%2B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B%5Cleft%28x%2B2%5Cright%29%5Cleft%28x-2%5Cright%29%7D%7Bx%2B2%7D%5C%20using%5C%20%28a%5E2-b%5E2%29%3D%28a%2Bb%29%28a-b%29%5C%5C%5C%5C%3Dx-2)
Hence, the quotient is (x-2).
Answer:
I think it's 140 not sure
Answer:
![Mean = 344](https://tex.z-dn.net/?f=Mean%20%3D%20344)
Step-by-step explanation:
Given
![Population = 1013](https://tex.z-dn.net/?f=Population%20%3D%20%201013)
Let p represents the proportion of those who worry about identity theft;
![p = 66\%](https://tex.z-dn.net/?f=p%20%3D%2066%5C%25)
Required
Mean of those who do not worry about identity theft
First, the proportion of those who do not worry, has to be calculated;
Represent this with q
In probability;
![p + q = 1](https://tex.z-dn.net/?f=p%20%2B%20q%20%3D%201)
Make q the subject of formula
![q = 1 - p](https://tex.z-dn.net/?f=q%20%3D%201%20-%20p)
Substitute ![p = 66\%](https://tex.z-dn.net/?f=p%20%3D%2066%5C%25)
![q = 1 - 66\%](https://tex.z-dn.net/?f=q%20%3D%201%20-%2066%5C%25)
Convert percentage to fraction
![q = 1 - 0.66](https://tex.z-dn.net/?f=q%20%3D%201%20-%200.66)
![q = 0.34](https://tex.z-dn.net/?f=q%20%3D%200.34)
Now, the mean can be calculated using:
![Mean = nq](https://tex.z-dn.net/?f=Mean%20%3D%20nq)
Where n represents the population
![Mean = 1013 * 0.34](https://tex.z-dn.net/?f=Mean%20%3D%201013%20%2A%200.34)
![Mean = 344.42](https://tex.z-dn.net/?f=Mean%20%3D%20344.42)
(Approximated)