<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
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Answer:
x = 4
Step-by-step explanation:
Given
=
( cross- multiply )
3x = 12 ( divide both sides by 3 )
x = 4
Answer:
Just multiply the number by the percentage.
Step-by-step explanation:
1. Make the percentage into a decimal (%50= 0.50)
2. Multiply the decimal by the number.
75% = 0.75
750 people / 0.75 = 1,000 people
There were 1,000 total people attending the game
H(x) = 6x
it gives you what x is so plug that in the equation to find it.
h(2/3) = 6(2/3)
h(2/3) = 6 × 2 ÷ 3
h(2/3) = 12 ÷ 3
h(2/3) = 4
so your answer is 4.
hope this helps, God bless!