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3 years ago

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There may be multiple answers here. please help

1 answer:

gogolik [260]3 years ago

6 0

I'm not positive I know the answer, but I have a feeling that because it's asking that you select all that apply, there is more than just one answer.

x + 3 = 0
-3 + 3 = 0

So yeah, just basically solve them as individual problems. Just do additive inverse for each expression.

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Can someone please help me on solving: x+y=-4

timama [110]

Answer: x=-1 and y= -3

Step-by-step explanation:

Solve for x, x+y=-4

Minus y from both sides so it'll be X=-y-4

Now substitute -y-4 in x-y=2 and solve for y

-y - 4 -y=2

Add like terms, -2y - 4=2

Add 4 to both sides -2y=6

Divide both sides by -2 $\frac{-2y}{-2} = \frac{6}{-2}$

y= -3

Substitute -3 in x=-y - 4

x=-(-3) - 4

- × (-3)= 3

3 - 4= -1

x= -1

5 0

2 years ago

DEF is a dilation image of ABC. What is the scale factor?

horsena [70]

Answer:

Option (2)

Step-by-step explanation:

ΔDEF is a dilation image of ΔABC.

Rule for the dilation,

Scale factor = $\frac{\text{Length of one side of the image triangle}}{\text{Length of one side of the original triangle}}$

= $\frac{DE}{AB}$

= $\frac{4}{8}$

= $\frac{1}{2}$

Therefore, scale factor by which ΔABC is dilated is $\frac{1}{2}$ .

Option (2) will be the correct option.

7 0

2 years ago

Plzz helpppppp222!!!!!!!!!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

The rectangle has 4 corners of 90 degrees.

Here a rectangle is divided into two right triangles. In right-angled triangles, the opposite side at a 30-degree angle is half a chord...I replace x instead of length.. So x / 2 = 4--->x:8

The perimeter of a rectangle is equal to (length + width) × 2--->(8+4)×2=24m^2

7 0

2 years ago

Read 2 more answers

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

2 years ago

Can you please help do not understand

o-na [289]

The first blank on the left side should be 0 I think

7 0

2 years ago