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nata0808 [166]
4 years ago
13

There may be multiple answers here. please help

Mathematics
1 answer:
gogolik [260]4 years ago
6 0
I'm not positive I know the answer, but I have a feeling that because it's asking that you select all that apply, there is more than just one answer.

x + 3 = 0
-3 + 3 = 0

So yeah, just basically solve them as individual problems. Just do additive inverse for each expression.
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A scientist claims that 9% of viruses are airborne.
Aleksandr [31]

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Step-by-step explanation:

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The mean of this sampling distribution of sample proportion is:

\mu_{\hat p}=p  

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>n</em> = 596

<em>p </em>= 0.09

As the sample size is quite large, i.e. <em>n</em> = 596 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by a Normal distribution.

The mean and standard deviation are:

\mu_{\hat p}=p=0.09\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.09(1-0.09)}{596}}=0.012

Compute the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% as follows:

P(\hat p-p>0.03)=P(\hat p>0.12)

                         =P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}>\frac{0.12-0.09}{0.012})\\\\=P(Z>2.5)\\\\=1-P(Z

Thus, the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.

5 0
3 years ago
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