We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
X² + c is actually a quadratic function.
And x² + c = 0, it usually has two zeros which are solutions.
But for when c = 0,
x² + c = 0
x² + 0 = 0
x² = 0
Taking the square root of both sides.
x = 0. Here it only has one zero.
So the function x² + c, only has one root for c = 0.
Answer:
Ok, so I hope I understood the task. Here goes nothing
Step-by-step explanation:
So, first we calculate the area of the big rectangle,
(√63+√28)*√45 = 15√35
Then we calculate the area of the small rectangle
√7*√5 = √35
Then we do this to get the area left
15√35 - √35 = 14√35
Then we take

That should explain it
Is this too old? um 715 toys per day times 5 equals 3575. 3575 times 3 is <span>10725. so the workers will make 10725 toys in 3 weeks.</span>