Solve the following equationsin¢-cos¢=0
1 answer:
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<h2>Answers:</h2>
Question 1: The equations share the same slope, but different y-intercepts.
Question 2: Option B (y = 2x + 1)
<h2>Explanations:</h2><h3>For Question 1:</h3>Both equations are written in slope intercept form.
The equations we have are:
Both equations share the same slope of 2. However, they have different y-intercepts.
y = 2x can be written as y = 2x + 0.
Usually if you only have the slope in your equation then the y-intercept is the origin, or (0, 0).
The second equation's y-intercept is -7. It takes 'b's place.
<h3>For Question 2: </h3>We are given a graph and we need to find a equation.
According to the graph, the line passes at (0, 1). 1 is the y - intercept.
Since y = 2x + 1 is the only option with 1 as the y - intercept, it should be the correct answer.
I'll do the slope as well to verify our answer.
I will use the points (-1, -1) and (1, 3).
The correct answer should be .
Hope this helps you.