The factors of 32 are / 1, 2, 4, 8, 16, and 32.
For example, y=x+4 and y=5x+2.
That would mean that x+4=y=5x+2.
Simplify it to x+4=5x+2.
x=5x-2
-4x=-2
x=1/2.
Now, plug x into one of the equations.
y=x+4
y=1/2+4
y=9/2.
Therefore, the POI is (1/2,9/2).
Answer:
Erik's average speed exceeds the speed limit by 6.91 miles per hour.
Step-by-step explanation:
Let suppose that Erik travels at constant speed. Hence, the speed (
), measured in miles per hour, is determined by following equation of motion:
(1)
Where:
- Distance, measured in miles.
- Time, measured in hours.
Please notice that a hour equals 60 minutes. If we know that 
and 
, then the speed of Erik is:
Which is 6.91 miles per hour above the speed limit.
Answer:
I think its the second one
Step-by-step explanation:
Answer:
x = 144
Step-by-step explanation:
What you need to remember about this geometry is that all of the triangles are similar. As with any similar triangles, that means ratios of corresponding sides are proportional. Here, we can write the ratios of the long leg to the short leg and set them equal to find x.
x/60 = 60/25
Multiply by 60 to find x:
x = (60·60)/25
x = 144
_____
<em>Comment on this geometry</em>
You may have noticed that the above equation can be written in the form ...
60 = √(25x)
That is, the altitude from the hypotenuse (60) is equal to the geometric mean of the lengths into which it divides the hypotenuse (25 and x).
This same sort of "geometric mean" relation holds for other parts of this geometry, as well. The short leg of the largest triangle (the hypotenuse of the one with legs 25 and 60) is the geometric mean of the short hypotenuse segment (25) and the total hypotenuse (25+x).
And, the long leg of the large triangle (the hypotenuse of the one with legs 60 and x) is the geometric mean of the long hypotenuse segment (x) and the total hypotenuse (25+x).
While it can be a shortcut in some problems to remember these geometric mean relationships, you can always come up with what you need by simply remembering that the triangles are all similar.
