Answer:
Step-by-step explanation:
5(y+4) = 4(y+5)
5y+20 = 4y + 20
5y = 4y
y=0
Answer:
Step-by-step explanation:
x = 1
(x^2-4x+3=0 or sin(x)=1)
x = 1
( x^2-4x+3=0 or sin(x)=1)
Whats the question exactly??
Step-by-step explanation:
In order to describe speed of an object, we must describe the average speed of the entire trip. It is equal to the distance moved divided by time taken.
If a person covers a distance of 1 km to the library in 15 minutes, we can find its average speed.
Firstly, we convert 15 minutes to hour, 15 min = 0.25 hours
Now, using formula of speed = distance/time
It means that the average speed of the person is 4 km/h. Hence, the given statement is true.
Answer:
The population standard deviation is not known.
90% Confidence interval by T₁₀-distribution: (38.3, 53.7).
Step-by-step explanation:
The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus .
Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,
- The area to the left of the lower end of the interval shall be .
- The area to the left of the upper end of the interval shall be .
Look up the t-score of the upper end on an inverse t-table. Focus on the entry with
- a degree of freedom of 10, and
- a cumulative probability of 0.95.
.
This value can also be found with technology.
The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:
,
where
- is the t-score at the upper end of the interval,
- is the unbiased estimate for the standard deviation, and
- is the sample size.
For this confidence interval:
Hence the width of the 90% confidence interval is
.
The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:
.