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Genrish500 [490]
3 years ago
7

what is 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 12 + 10 + 1 + 8 + 6 + 5 + 8 + 1 + 16 + 84 + 6 + 10 + 10 + 10 + 10

+ 10 equals what?​
Mathematics
2 answers:
Vanyuwa [196]3 years ago
8 0

Answer:

317

Step-by-step explanation:

natta225 [31]3 years ago
7 0

Answer:

317

Step-by-step explanation:

10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 12 + 10 + 1 + 8 + 6 + 5 + 8 + 1 + 16 + 84 + 6 + 10 + 10 + 10 + 10 + 10 = 317

group all the tens together to make it easier.

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Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

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AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

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Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

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