All categories

3 years ago

Tính đạo hàm của y=2x-1-căn3x-0

Mathematics

1 answer:

adoni [48]3 years ago

7 0

Answer:

The derivative is

$\frac{dy}{dx} = 2 - \frac{2\sqrt3}{\sqrt x}\\$

Step-by-step explanation:

The function is given by

$y = 2x - 1 - \sqrt {3x}$

Differentiate with respect to x, we get

$\frac{dy}{dx} = 2 - 0 - \frac{2\sqrt3}{\sqrt x}\\\\\frac{dy}{dx} = 2 - \frac{2\sqrt3}{\sqrt x}\\$

You might be interested in

Dwight deposits $150 into his new savings account. The account earns 5% interest compounded annually.

GrogVix [38]

Answer:

$A=\$150(1.05)^{t}$

Step-by-step explanation:

we know that

The compound interest formula for this problem is equal to

$A=P(1+r)^{t}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods in years

in this problem we have

$P=\$150\\ r=5\%=0.05$

substitute in the formula above

$A=\$150(1+0.05)^{t}$

$A=\$150(1.05)^{t}$

8 0

3 years ago

-4(3 - 2x) + 2x = 2x - 8

Dennis_Churaev [7]

Answer:

C) x = ½

Step-by-step explanation:

Using the <em>Distributive Property</em> and combining like-terms will give you this:

-12 + 10x = 2x - 8

- 10x -10x

--------------------

-12 = -8x - 8

+ 8 +8

-------------

-4 = -8x [Divide by -8]

½ = x

I am joyous to assist you anytime.

4 0

3 years ago

At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric

Zanzabum

Answer:

a) (1215, 1297)

b) (1174, 1338)

c) (1133, 1379)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

Also known as 68-95-99.7 rule.
It states that almost all the data lies within three standard deviation for a normal data.
About 68% of data lies within 1 standard deviation of mean.
About 95% of data lies within two standard deviation of mean.
About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

$\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)$