Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
Answer: -2, 0 and 0, 2 and 2, 4
Step-by-step explanation:
Answer:
The width is 11 units.
Step-by-step explanation:
First, you have to add 4 to 18 which is 22. Then divide by 2.
If I were you, I would search it up on VirtualNerd but you first undo using the opposite of PEDMAS and if you divide or multiply with a negative integer, the direction of the inequality thing in the middle of the equation switches directions.
Answer:
no solutions
Step-by-step explanation:
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