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fomenos
2 years ago
7

THE PROBABILITY OF A FOOTBALL TEAM WINNING A MATCH IS 0.3 THE PROBABILTITY OF THE SAME FOOTBALL TEAM LOSING IS 0.55 WHAT IS THE

PROBABILITY OF THE SAME FOOTBALL TEAM WINNING THE MATCH?
Mathematics
1 answer:
Sav [38]2 years ago
5 0

Answer:

P(Win) = 0.30

Step-by-step explanation:

Given

P(Win) = 0.30

P(Lose) = 0.55

Required

P(Win)

This is already stated in the question as:

P(Win) = 0.30

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Find the perimeter of a rectangle that is 7 centimeters long and 7 centimeters wide
spayn [35]

Answer:

28cm

Step-by-step explanation:

2L+2W=

14+14=28

(It’s a square)

4 0
3 years ago
I need the help of identifying the constant term and numerical coefficient in this expression
aalyn [17]

Answer:

constant term:n

numerical coefficient:2

Step-by-step explanation:

a numerical coefficient is a fixed number that is multiplied to a variable. So in the expression, the numerical coefficient would be 2

A constant term is something in an algebraic expression that does not change which is n

3 0
3 years ago
Read 2 more answers
Help a bab out please?
Volgvan

Answer:

HI

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]
Anit [1.1K]

Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\

\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to  c= - \frac{1}{2}

put the value of c in equation (i):

\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\

In equation (ii) multiply by 3 then subtract by equation (iv):

\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\

put the value of d in equation (iv):

\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2

The final answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

4 0
3 years ago
What is 10 more than 451
TEA [102]
10 more than 451 would be 451 + 10 = 461.


6 0
3 years ago
Read 2 more answers
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