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Troyanec [42]
3 years ago
7

HEEEEELPPPPPPPPPPPP ASAP

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0
Answer is A 15$=1 hour
30$=2 hours
45$=3 hours and so on
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What is the area of the trapezoid?
Naily [24]
40,960

hope this helps

:)

5 0
3 years ago
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Solve the following question using the elimination method :)
pochemuha
The one above me is correct
8 0
3 years ago
If you make a 25% of discount how much money do you subtract?
pantera1 [17]
Lets say u want an item that originally cost $ 50.....and u get a 25% discount....then u are actually subtracting 25% of the original price.

25% of 50 .....turn the percent to a decimal..." of " means multiply
0.25 * 50 = 12.50.....so u would be subtracting 12.50 from $ 50 for the discounted price which is (50 - 12.5) = 37.5

here is another example...
u want an item that costs $ 90....and it is 25% off.....so u would be subtracting (25% of 90).......u would be subtracting (0.25 * 90) = 22.50 from the original price to arrive at the discounted price.
90 - 22.50 = 67.50...the discounted price

But let me show u something....taking 25% off is the same as paying 75%..
so lets say u want an item that costs $ 60....and u get a 25% discount...this means u r actually paying 75%.....ur paying 75% of 60.
0.75 * 60 = $ 45...this is what u r paying....no need for subtracting 

8 0
3 years ago
Read 2 more answers
The sum of a number times 9 and 16 is at least -26.
NARA [144]

Answer:

Step-by-step explanation:

let x be the number.

9x+16≥-26

9x≥-26-16

9x≥-42

3x≥-14

x≥-14/3

5 0
2 years ago
Find the non-extraneous solutions of the square root of the quantity x plus 6 minus 5 equals quantity x plus 1.
sdas [7]
The radical equation is \sqrt{x+6}-5=x+1.


i) We first isolate the square root, adding 5 to both sides of the equation: 
       
                                        \sqrt{x+6}=x+6.

ii) Here let's substitute x+6 with t. Doing so we have:
 
                                         \sqrt{t}=t.

Squaring both sides, we get:
                       
                                               t=t^2

iii) Collecting the variables on the same side, and factorizing t we have:
 
                                               t(t-1)=0, which yields

                              t=0    or       t=1.

Now we solve for x in x+6=t:

x+6=0 ⇒x=-6       and x+6=1⇒x=-5.


iv) Now we check these values in the original equation  \sqrt{x+6}=x+6 :

a) \sqrt{-6+6}=-6+6. ⇒ 0=0 ; Correct.


b) \sqrt{-5+6}=-5+6. ⇒ 1=1 ; Correct.



Answer: <span>x = −6 and x = −5 </span>
5 0
3 years ago
Read 2 more answers
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