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2 years ago

6

A scatterplot is used to display data for a runner where x is the number of miles run, and y is the time, in minutes, that it ta

kes to run that distance.
Which interpretation describes a line of best fit of y = 9.5x for the data in the scatterplot?

1 answer:

Effectus [21]2 years ago

6 0

Answer:

Answer: A the member can tolerate a temp of 173 fahrenheit for 0 minutes

Step-by-step explanation:

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Determine the currents in the picture

Elenna [48]

Answer:

The value of currents are $I_1=0A$ , $I_2=1A$ and $I_3=1A$ .

Step-by-step explanation:

The Ohm's law states that

$V=IR$

it is given that the V₁=3V and V₂=4V.

In a parallel circuit:

Voltage is same in each component

Sum of the currents equals to the total current that flows.

$I_2=I_1+I_3$ .... (1)

Equation for first loop is,

$V_1=4I_1+3I_2$

$3=4I_1+3I_2$ ..... (2)

Equation for second loop is,

$V_2=1I_3+3I_2$

$4=1I_3+3I_2$ ..... (3)

On solving (1), (2) and (3) we get

$I_1=0$

$I_2=1$

$I_3=1$

Therefore the value of currents are $I_1=0A$ , $I_2=1A$ and $I_3=1A$ .

6 0

2 years ago

I need help asap please

Leya [2.2K]

Answer:

the answer is that of equations 1

6 0

3 years ago

Read 2 more answers

Sarah is 6 years older than Amy.

Umnica [9.8K]

Answer:

B.

Step-by-step explanation:

The problem has got to be addition.

The sentence "Sarah is 6 years older than Amy." does not include any hint of subtracting, or multiplying.

A hint of multiplying in a expression would be the word 'times', like "Brandon is 6 times the age of Emily" which eliminates D.

A hint of subtraction in an expression would be the word 'less', like "Brandon is 6 less the age of Emily." which eliminates A and C.

The word 'older' indicates addition, or adding, and if it would have been subtraction, the keyword would be 'younger' because you are subtracting their age, like 19 - 11. The same goes with B, but adding.

Finally, we now know that it is B because there is no other addition choice.

I hope this helped. Please correct me if I am wrong.

8 0

3 years ago

What is the value of C in the matrix equation below?

lara [203]

Given:

The matrix equation is:

$\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}$

To find:

The value of matrix C.

Solution:

Let $A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}$ . Then the given equation can be rewritten as

$A-C=B$

$-C=B-A$

$C=-(B-A)$

$C=A-B$

On substituting the values of the matrices, we get

$C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}$

$C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}$

$C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}$

$C=\begin{bmatrix}-4&2&-7\end{bmatrix}$

Therefore, the correct option is C.

6 0

2 years ago

Read 2 more answers