Answer:
Don't respond to it. Either leave it there, or just delete it. It is most likely spam or a scammer trying to get your information. Don't respond, please.
When you don't know the answer to a question, a good incident management strategy is to tell the user that you'll research the question and get back to him or her.
<h3>What is
incident management?</h3>
Incident management can be defined as a strategic process through which a business organization or company identifies, analyzes, and correct hazards, so as to ensure that normal service operation is restored as quickly as possible to end users after a disruption, as well as to prevent a re-occurrence of these hazards in the future.
As a support agent, if you don't know the answer to a question, a good incident management strategy is to tell the user that you'll research the question and get back to him or her at a latter time.
Read more on incident management here: brainly.com/question/11595883
the answer is True
there has to be a balance between security and the user experience
user_str1 = str ( input ("Please enter a phrase: "))
user_str2 = str ( input("Please enter a second phrase: "))
def strcmp (word):
user_in1 = int (len(user_str1))
user_in2 = int (len(user_str2))
if user_in1 > user_in2:
return "Your first phrase is longer"
elif user_in1 < user_in2:
return "Your second phrase is longer"
else:
return "Your phrases are of equal length"
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
