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Black_prince [1.1K]
3 years ago
5

The area of a rectangle is 2x*2-13x+12 and another area is 6x^2-13x+21, what is the combined area of both rectangles?

Mathematics
1 answer:
saul85 [17]3 years ago
8 0

Answer:

8x^2 - 26x + 33

Step-by-step explanation:

Add the expressions.

2x^2 - 13x + 12 + 6x^2 - 13x + 21 =

= 2x^2 + 6x^2 - 13x - 13x + 12 + 21

= 8x^2 - 26x + 33

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otez555 [7]

Answer:

A function can be any set of points where one input is equal to one output. You cannot have two X values with the same Y value, for example.

<u>I believe the answer is neither</u> because in both sets you can see they have different Y values for the X values 2 and 9.

6 0
3 years ago
Pls tell the answer for 50 points!
White raven [17]

Answer:

7*11^5

Explanation:

(the photo)

5 0
2 years ago
Number of data values: 1007
kogti [31]

Answer:

The arithmetic mean is 10.9

Step-by-step explanation:

In this question, we are tasked with calculating the arithmetic mean using the information given.

The arithmetic mean or otherwise called the average is the sum of all the values in a given set divided by the number of elements or count of the elements in that particular data set

Mathematically, the arithmetic mean can be found by dividing the sum of the data values by the number of data values.

In equation form, we have Arithmetic -mean = \frac{sum of data values}{number of data values}

Inserting the values, we have Arithmetic mean = 10998/1007 = 10.92 which is 10.9 to the nearest tenth

5 0
3 years ago
Question 1
Ilia_Sergeevich [38]

We will see that the perimeter of the rectangle is exactly 390 ft, so the statement is true.

<h3>Is the fence enough?</h3>

For a rectangle of length L and width W, the perimeter is given by:

P = 2*(L + W).

In this case, we know that:

L = 120 ft

W = 75 ft

Replacing that on the perimeter equation we get:

P = 2*(120 ft + 75  ft) = 390 ft

So the perimeter is exactly 390 ft, meaning that to put a fence around the parking lot the company will need at least 390 ft of fence.

So the statement is correct.

If you want to learn more about perimeters, you can read:

brainly.com/question/24571594

4 0
2 years ago
F(x)=x+3 , G(x)=x^2-2<br> (F/G)(-1)-G(3)
trapecia [35]

f(x)=x+3;\ g(x)=x^2-2\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=?\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\g(3)=3^2-2=9-2=7\\\\f(-1)=-1+3=2\\\\g(-1)=(-1)^2-2=1-2=-1\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=\dfrac{2}{-1}-7=-2-7=-9

7 0
3 years ago
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